On Fri, Oct 11, 2013 at 4:06 PM, Leonardo Giordani <[email protected]> wrote: > I think that you have to perform a query for each Code, extracting the list > of Word matching that Code and then merging all the lists.
Exactly! > Since I don't know your models, I'll give you some general code, let me know > if you understand how to implement it exactly on your models. Here are these two models: http://tny.cz/82158e83 <snip> > This is the basic algorithm. You can then make all sorts of Python magic > tricks to shorten it or make it faster, but if you are not dealing with > billions of data I do suggest you to keep it simple and readable. Ok. > If you need to have each element in B appear just one time (uniqueness) just > perform a B = set(B) at the end. Ok. > Let me know if it works. =) Yes it will work! But after extending list B, I want to search the elements of list B from UserProfile table. Here the word can be anywhere and can be more than one times. Also two words in list B can be in same column. Here also the results must be unique. Also how to get the output in a template? The tuples containing elements of list B from UserProfile table are to be displayed in that template. Thanks ^_^ -- Kamaljeet Kaur -- You received this message because you are subscribed to the Google Groups "Django users" group. To unsubscribe from this group and stop receiving emails from it, send an email to [email protected]. To post to this group, send email to [email protected]. Visit this group at http://groups.google.com/group/django-users. To view this discussion on the web visit https://groups.google.com/d/msgid/django-users/CAP8Q%2BxidZD%2B6mo2z4POabcX_WBFPvEk%3D%3Dg%2BOPNET6u0SYmM%3DkQ%40mail.gmail.com. For more options, visit https://groups.google.com/groups/opt_out.
