Thanks Lucas, sorry for not being clear, I like not to include the object
when the name is matching, I figured out that can be done to use
user_list.exclude, not user_list.filter. It is working currently in an
inefficient way:
for user in user_object_list:
if user.is_locked():
user_list = user_list.exclude(user__name=user.name)
Is there anyway to filter out all users to match the user exclude list in
one statement such as following example (wrong syntax I guess):
for user in user_object_list:
if user.is_locked():
user_exclude_list.append(user.name)
user_list = user_list.exclude(user__name.icontain=user_exclude_list)
Thank you.
On Friday, April 11, 2014 4:26:23 AM UTC+10, Lucas Klassmann wrote:
>
> Hi,
>
> If you want exact match:
>
> user_list.filter(user__name__iexact=user.name)
>
>
> Or containment test:
> user_list.filter(user__name__icontains=user.name)
>
>
> Note that "i" on start is for case-insensitive filtering.
>
> Look here for more information:
> https://docs.djangoproject.com/en/dev/topics/db/queries/
>
>
> Cheers
>
>
> On Thu, Apr 10, 2014 at 2:38 PM, carlos <[email protected]
> <javascript:>>wrote:
>
>> hi, maybe you filter you queryset
>> user_list = Model.objects.filter(user__name=user.name
>> ).filter(other__field=user.email)
>>
>> Cheers
>>
>>
>> On Thu, Apr 10, 2014 at 9:44 AM, nobody <[email protected] <javascript:>
>> > wrote:
>>
>>> Hi,
>>>
>>> How can I filter an item from the queryset object list if the name is
>>> matching? The following won't work.
>>>
>>> user_list.filter(user__name=user.name)
>>>
>>> Thank you.
>>>
>>>
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>
>
> --
> Lucas Klassmann
> Desenvolvedor de Software
>
> Email: [email protected] <javascript:>
> Web site: http://www.lucasklassmann.com
>
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