On Wednesday, May 14, 2014 11:35:46 PM UTC-7, G Z wrote:
>
> So I read the documentation on passing csrf tokens, however its giving me
> an issue i think its because im trying to pass it as a dictonary variable
> with my form and customers.
>
> This is from the documentation
>
> from django.views.decorators.csrf import csrf_protectfrom django.shortcuts
> import render
> @csrf_protectdef my_view(request):
> c = {}
> # ...
> return render(request, "a_template.html", c)
>
>
>
> from django.shortcuts import render
> from django.http import HttpResponse
> from vmware.models import Customer
> from django.shortcuts import render_to_response
> from vmware.models import Vms
> from .forms import SignUpForm
> from vmware.models import Vmspecs
> from django.views.decorators.csrf import csrf_protect
>
> @csrf_protect
> def index(request):
> c = {}
> form = SignUpForm(request.POST or None)
> if form.is_valid():
> save_it = form.save(commit=False)
> save_it.save()
> customers = Customer.objects.all()
> ctx = { 'customers':customers, 'form':form, c}
> return render_to_response('index.html', ctx)
>
>
>
> this is the error i get
>
>
> Environment:
>
>
> Request Method: GET
> Request URL: http://23.239.206.142:8000/
>
> Django Version: 1.6.4
> Python Version: 2.7.3
> Installed Applications:
> ('django.contrib.admin',
> 'django.contrib.auth',
> 'django.contrib.contenttypes',
> 'django.contrib.sessions',
> 'django.contrib.messages',
> 'django.contrib.staticfiles',
> 'vmware')
> Installed Middleware:
> ('django.contrib.sessions.middleware.SessionMiddleware',
> 'django.middleware.common.CommonMiddleware',
> 'django.middleware.csrf.CsrfViewMiddleware',
> 'django.contrib.auth.middleware.AuthenticationMiddleware',
> 'django.contrib.messages.middleware.MessageMiddleware',
> 'django.middleware.clickjacking.XFrameOptionsMiddleware')
>
>
> Traceback:
> File "/usr/local/lib/python2.7/dist-packages/django/core/handlers/base.py"
> in get_response
> 101. resolver_match = resolver.resolve(request.path_info)
> File "/usr/local/lib/python2.7/dist-packages/django/core/urlresolvers.py"
> in resolve
> 337. for pattern in self.url_patterns:
> File "/usr/local/lib/python2.7/dist-packages/django/core/urlresolvers.py"
> in url_patterns
> 365. patterns = getattr(self.urlconf_module, "urlpatterns",
> self.urlconf_module)
> File "/usr/local/lib/python2.7/dist-packages/django/core/urlresolvers.py"
> in urlconf_module
> 360. self._urlconf_module = import_module(self.urlconf_name)
> File "/usr/local/lib/python2.7/dist-packages/django/utils/importlib.py" in
> import_module
> 40. __import__(name)
> File "/root/djangoprojects/provisioning/provisioning/urls.py" in <module>
> 7. url(r'^customers/', include('vmware.urls')),
> File "/usr/local/lib/python2.7/dist-packages/django/conf/urls/__init__.py"
> in include
> 26. urlconf_module = import_module(urlconf_module)
> File "/usr/local/lib/python2.7/dist-packages/django/utils/importlib.py" in
> import_module
> 40. __import__(name)
> File "/root/djangoprojects/provisioning/vmware/urls.py" in <module>
> 5. from vmware import views
>
> Exception Type: SyntaxError at /
> Exception Value: invalid syntax (views.py, line 19)
>
>
>
Specifically, you're passing 'c' into the ctx dictionary, but it has no
key, that's the syntax error. But that c dictionary is redundant anyway
since you've created your own context dictionary. Just remove the
declaration of that object and don't pass it into the dictionary.
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