I'm writing a rudimentary exercise app in django, with the following table structure:
Routine Exercise Segment ===== ===== ===== routine_name exercise_name routine_id (fk) routine_id exercise_id exercise_id (fk) order duration * (fk) = foreign key In practice, this looks as follows: <https://lh3.googleusercontent.com/-TBTlJazPPBA/VDSaG6O_PFI/AAAAAAAAAUE/UftSycm-NYg/s1600/Screen%2BShot%2B2014-10-06%2Bat%2B8.48.54%2BPM.png> A Routine contains numerous Segments, and each segment contains one Exercise, the order number (where the segment appears in the routine – first, second, third, etc), and the duration of that segment. My question is, is there an way to allow someone to add a new exercise type from the "Add routine" view? I.e., if I'm making a new routine, I don't necessarily want to have to drop out and go to the Exercise table view to add a new exercise to the list. Thanks in advance! Elli *Note: This was cross-posted to StackOverflow <http://stackoverflow.com/questions/26227062/insert-to-foreign-key-linked-table-in-django-admin-interface>, with very few views there. I thought I'd try here as well.* -- You received this message because you are subscribed to the Google Groups "Django users" group. To unsubscribe from this group and stop receiving emails from it, send an email to [email protected]. To post to this group, send email to [email protected]. Visit this group at http://groups.google.com/group/django-users. To view this discussion on the web visit https://groups.google.com/d/msgid/django-users/4955d625-d898-4fdf-b186-a8db536363b9%40googlegroups.com. For more options, visit https://groups.google.com/d/optout.
