I am trying to create version for REST application. Here is my URL Examle
www.myapi.com/foo [default version]
www.myapi.com/v1/foo [version one]
This is the project structure
├── __init__.py├── settings.py├── urls.py├── default_app│ ├── __init__.py│ ├──
serializer.py│ ├── models.py│ ├── views.py│ ├── urls.py│ └── v1_app├──
__init__.py├── serializer.py├── models.py├── views.py├── urls.py
*default_app urls.py*
from django.conf.urls import *from default_app import views as df_viewsfrom
rest_framework import routers
router = routers.DefaultRouter()
router.register(r'foo', df_views.viewname, "foo")
urlpatterns = router.urls
*v1_app urls.py*
from django.conf.urls import *from v1_app import views as ver_viewsfrom
rest_framework import routers
router = routers.DefaultRouter()
router.register(r'foo', ver_views.viewname, "foo")
urlpatterns = router.urls
*main file for urls.py*
from django.conf.urls import patterns, include, urlfrom defualt_app import urls
as default_urlsfrom v1_app import urls as v1_urlsfrom
django.contrib.staticfiles.urls import staticfiles_urlpatterns
urlpatterns += patterns('',
url(r'^', include(default_urls, namespace="default")),
url(r'^v1/', include(v1_urls, namespace="v1")))
urlpatterns += staticfiles_urlpatterns()
My issue is, when i using simple url without any prefix then it is working
www.myapi.com/foo
and when i used version prefix v1 or v2 then it throws error [Page not
found (404)]
www.myapi.com/v1/foo
I got this idea from this link http://stackoverflow.com/a/21839842/1558544
If I don't use middleware class then is this possible to get same result?
Thank you
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