You should be able to query it as a ForeignKey

Jobs.objects.filter(names__is_a_problem=True).distinct()

(distinct to prevent repeated jobs with more than one worker problem)


On Wed, Dec 23, 2015 at 9:31 AM, Jonty Needham <[email protected]>
wrote:

> I have a model of the form:
>
> class Jobs(models.Model):
>         names  = models.ManyToManyField(Workers)
>
> class Workers(modesl.Model):
>      is_a_problem = True
>
>
> And I want the set of jobs that are done by workers who are a problem.
>
> Something like
>
>
> Jobs.objects.filter(names__is_contained_in=Workers.objects.filter(is_a_problem=True))
>
> Obviously is_contained_in is not a valid lookup, so I would like to know
> how to do this please.
>
> Thanks
> Jonty
>
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