samuel wrote: >>> I'm probably just not seeing it, but how do I go about getting the >>> index of an item in a query set? I.E., this article is the Xth article >>> in this queryset of articles sorted by date. >> If you're looping through them in the template with the 'for' tag, >> each time through the loop you'll have access to a variable called >> 'forloop.counter' which has this information; the first time through >> it will be 1, the second time it will be 2, and so on. >> >> See http://www.djangoproject.com/documentation/templates/#for for details. >> > > Thanks but I guess I'm looking for something a bit different. Here's > exactly what I'm trying to do: I have articles that are chunked into > groups of 10 arbitrarily based on their date. So when a new article is > added the groups change. When you go to an article page, I want to > display the chunk that the article belongs to. So if the article is > 19th, display a list of articles 11-20. > > If I'm thinking through this correctly, I need to know the articles > location in the queryset before I get to the template and then slice > the queryset as necessary. How would I go about this? Just iterate > through and backtrack when I get there? >
if the number of articles is not too high, then simply generate their number in the view... like: queryset = Article.objects.all() items = list(enumerate(queryset)) which is basically the same as: items = zip (range(queryset.count()), queryset) or, if you want it 1-based and not 0-based: items = zip (range(1,queryset.count()+1), queryset) the problem with these is that it fetches all the article-objects. gabor --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to [email protected] To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users -~----------~----~----~----~------~----~------~--~---
