I already got one fast and helpful answer today, so I’m going to be greedy
and press my luck.
I have this website. Each state has their own home/landing page off the
site’s main page, and from there you will be able to get detail pages about
various tidbits about the state of your choice. I have implemented this
with a urlconf that looks for the state’s 2 digit postal name:
url(r'^(?P<twodigit>[A-Z]{2})', include('bench.urls', namespace=twodigit)),
It will come as no surprise that the views and templates associated with
each state are identical. However, in order to be DRY, I wanted the view to
take the twodigit argument from the url and call the right state’s
queryset. To this end, I created a dict
{'AK': 'Alaska',
'AL': 'Alabama',
'AR': 'Arkansas',
...etc…}
naively thinking I would be able to do something like
for k,v in statedict:
if twodigit == k:
state = Jurisdiction.objects.get(v)
However, this does not work. I’m not sure why. Here are some of the various
results I’ve gotten as I tried tweaking it:
for k,v in statedict:
if 'VA' == k: # I was thinking of this as almost a default value
state = Jurisdiction.objects.get(v)
However, this gets an unbound local error because of the scope, and I don’t
know how to assign the variable so that it is accessible outside the scope
of the for loop.
k='NE'
print(v)
k=="US"
print(v)
returned
U
U
Clearly, there is no ‘U’ in Nebraska, so I don’t know what happened there.
This works
print(statedict['US'])
(aishah) malikarumi@Tetuoan2:~/Projects/aishah/jamf35$ python statedict.py
United States
But this does not
File "statedict.py", line 63, in <module>
if statedict['k']:
KeyError: 'k'
And this
for k, v in statedict:
if k:
print('v')
Gets me a ‘v’ for every state.
Variations on
Jurisdiction.objects.filter(statedict[’v']) and
Jurisdiction.objects.filter(name='v’)
also failed, and nothing I have found on the internet has helped. Ideas?
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