Building.objects.filter(addresses__street__pk=patientid) will return all buildings with an address in the same street as the patient. If I understand correctly, that is :)
2017-01-26 10:41 GMT+01:00 Richard Hall <[email protected]>: > Thanks for replying, I need all the help I can get. What I'm trying to do is > the opposite of what I seem to be doing. Rather than looking for an address > without a building I am trying to see, from my list of all buildings, which > one has an address (filtered by patientid). I can easily list all addresses > associated with a building, it is just getting only the ones for a > particular patient that I'm stuck with. > > Thanks, > > Richard > > -- > You received this message because you are subscribed to the Google Groups > "Django users" group. > To unsubscribe from this group and stop receiving emails from it, send an > email to [email protected]. > To post to this group, send email to [email protected]. > Visit this group at https://groups.google.com/group/django-users. > To view this discussion on the web visit > https://groups.google.com/d/msgid/django-users/0ec5c059-a0b3-41ab-8f42-2603e0d640e5%40googlegroups.com. > > For more options, visit https://groups.google.com/d/optout. -- Cordialement, Coues Ludovic +336 148 743 42 -- You received this message because you are subscribed to the Google Groups "Django users" group. To unsubscribe from this group and stop receiving emails from it, send an email to [email protected]. To post to this group, send email to [email protected]. Visit this group at https://groups.google.com/group/django-users. To view this discussion on the web visit https://groups.google.com/d/msgid/django-users/CAEuG%2BTZP_XHQYeHJ9_FQGCBrn8S%2Bt3zfMbyf%2BHR4F8-02CsWzg%40mail.gmail.com. For more options, visit https://groups.google.com/d/optout.
