Hi,
What is JSONField? Is it part of Django or from a third party package?
On Monday, April 3, 2017 at 10:34:18 AM UTC-4, Martin Peveri wrote:
>
> Hi, I have this model:
>
> class ItemCampaign(models.Model):
>
> campaign = models.ForeignKey(
> Campaign, related_name="itemscampaign", verbose_name="Item campaña"
> )
> data = JSONField(default=dict)
>
> def __str__(self):
> return self.campaign.name
>
> With a record with this data:
>
> [{'number': '1160188479', 'id': 0, 'content': 'hello', 'processed': True},
> {'number': '1160188479', 'id': 1, 'content': 'hello', 'processed': False
> }, {'number': '1160188479', 'id': 2,'content': 'hello', 'processed': False
> }, {'number': '1162341721', 'id': 3, 'content': 'hello', 'processed':
> False}, {'number': '1162341721', 'id': 4, 'content': 'hello', 'processed':
> False}, {'number': '1162341721', 'id': 5, 'content': 'hello', 'processed':
> False}]
>
> I want filter this list dict, like this:
>
> c.itemscampaign.filter(data__processed=True)
>
> But not work. That does not give me back anything.
>
> The content type of data is:
>
> >>> type(c.itemscampaign.all()[0].data)
> <class 'list'>
>
> I understand that it has to be a dict, but how can I insert many
> dictionaries in the field, as I have in my data if it is not in a list?
>
> Thanks!
>
>
>
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