Andrew, your solution works great for one brand. But I have more than one.
суббота, 20 мая 2017 г., 0:20:18 UTC+5 пользователь Andrew Beales написал:
>
> brand = Brand.objects.get(title='mybrand')
> products = Product.objects.filter(brand=brand).order_by('-score')[:4]
>
> ...gets you the top 4 products in order for the brand
>
> On Friday, May 19, 2017 at 10:32:49 AM UTC+1, Горобец Дмитрий wrote:
>>
>> Hello. I have these two models. I have to show 4 or less products on a page
>> for each brand ordered by score. Please, help construct correct queryset.
>>
>>
>>
>> class Brand(models.Model):
>> title = models.CharField(
>> verbose_name='Название бренда',
>> max_length=64,
>> unique=True,
>> db_index=True,
>> error_messages={
>> 'unique': 'Бренд с таким именем уже существует.'
>> }
>> )
>>
>> slug = AutoSlugField(
>> verbose_name='Адрес страницы бренда',
>> populate_from='title',
>> editable=True,
>> unique=True,
>> slugify=custom_slugify,
>> db_index=True
>> )
>>
>> owner = models.OneToOneField(
>> to=settings.AUTH_USER_MODEL,
>> verbose_name='Владелец',
>> on_delete=models.PROTECT,
>> )
>>
>>
>> score = models.DecimalField(
>> verbose_name='Рейтинг бренда',
>> blank=True,
>> null=True,
>> max_digits=19,
>> decimal_places=18,
>> )
>>
>>
>>
>> class Product(models.Model):
>> title = models.CharField(
>> verbose_name='Название изделия',
>> max_length=255,
>> db_index=True,
>> )
>>
>> slug = AutoSlugField(
>> verbose_name='Адрес страницы изделия',
>> populate_from='title',
>> editable=False,
>> unique_with='brand',
>> slugify=custom_slugify,
>> db_index=True,
>> )
>>
>> brand = models.ForeignKey(
>> to=Brand,
>> verbose_name='Бренд',
>> related_name='products',
>> on_delete=models.CASCADE,
>> )
>>
>>
>>
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