Thanks for your response. I was pondering on option a before posting this
query thinking there could be better ways in django/SQL to handle this. But
now I would probably go with a.
On Friday, February 2, 2018 at 7:50:53 PM UTC+5:30, Andy wrote:
> a) Maybe its an option to put the foreign key to the other model? This way
> you dont need to make a join to find out if there is a relation.
> b) Save the existing ralation status to model A
> c) cache the A.objects.filter(bs__isnull=False) query
> But apart from that i fear you cannot do much more, since this is just a
> DB and not a Django ORM question.
> Am Freitag, 2. Februar 2018 14:47:45 UTC+1 schrieb Web Architect:
>> I am trying to optimise Django queries on my ecommerce website. One of
>> the fundamental query is where I have no clue how to make efficient. It
>> could be trivial and probably been known long time back. But I am new to
>> Django and would appreciate any help. This is primarily for one to many or
>> many to many relations.
>> Following is an example scenario:
>> (Please pardon my syntax as I want to put across the concept and not the
>> exact django code unless it's really needed):
>> Model A:
>> class A(models.Model):
>> # Fields of model A
>> Model B (which is related to A with foreign key):
>> class B(models.Model):
>> a = models.ForeignKey('A', related_name='bs')
>> Now I would like to find out all As for which there is atleast one b. The
>> only way I know is as follows:
>> But the above isn't an optimal way as with large of records in A and B,
>> the above takes lot of time. It gets more inefficient if it's a many to
>> many relationship.
>> Could anyone please let me know the most efficient way to use django
>> queryset for the above scenario?
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