On Monday, 4 June 2018 16:00:09 UTC+10, Bernd Wechner wrote: > > Say I have a page on my Django website (because I do) that I would like to > take a snapshot of on an automated basis on the server itself with a > crontab say. I imagine writing a small python script that I could run, that > loads Django, a settings file, knows a URL and has a way of saying "give me > the rendered page for that URL please" and save it in a file. > > On way of course is open port 80 or 443, send an HTTP request and get the > HTTP response. But there is probably a better way that leaves the web and > UWSGI servers right out of the equation and just runs Django template > rendering code or a view itself and nabs the result. > > As usual, I'm both confident this is possible and that I'll nut out a way > to do it, but am throwing it out there in case: > > a) there's a canonical way to do this already that can be recommended > b) I can save myself some time reading and experimenting if anyone whose > done this already shares their experience > > I will raise the bar one on the original question while I'm here, and > raise the spectre of autorun on page load javascript that the page may > have. Makes it hairier by a step. But it's not unusual for javascript to do > some rendering on page load - I have a page or two like that ;-), In that > case neither of these strategies are likely to work and either one might if > coupled with what would basically need to be, a rendering engine like > mozilla's. Does Python offer that I wonder, a way to pump a response (with > embedded Javascript) into a rendering engine and then save (or request) the > rendered page? > > Kind regards, > > Bernd. >
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