vi is just a variable that I created in my code.  It is just short for visit.  It has NOTHING to do with the vi editor program.  My editor is Geany.

I am using the Django ORM to query my database.


On Wednesday, 08 August, 2018 01:45 AM, Kidwell Nyatsambo wrote:
Hello,
Which application / program uses vi. I would like to create a schema.sql to use with Python.

KN

On Mon, Aug 6, 2018 at 4:08 PM, Gerald Brown <[email protected] <mailto:[email protected]>> wrote:

    This is how I finally solved my problem!!!

    The following is a copy of my ORM statement:

     Visit.objects.filter(visit_date = mydate).aggregate(total =
    Sum('visit_payment'))
    {'total': Decimal('27')}
     This total is the total of the foreign key ids.  9 records each
    with a key of 3 = 9 x 3 = 27

    The way I solved this problem is to put another variable in the
    loop where I was printing the records to Reportlab PDF file and I
    incremented this variable with the value that was being printed. 
    What was being printed was the value from the look-up table so I
    was able to get a Sum from that.

    Here is the code of how I did it: vi =
    Visit.objects.filter(visit_date = mydate);  vip = 0; for v in vi:;
    vi_pay = str(v.visit_payment); vip += int(vi_pay)

    Here is how the Reportlab is built: Also in the same loop as above
    I have the lines:  vi_pat = str(v.patient); pa1.drawString(x, y,
    str(vi_pat)); pa1.drawString(x + 175, y, str(vi_pay))

    Each of these are on a separate line in my code.

    Hopefully this will help anyone with similar problems.


    On Monday, 06 August, 2018 09:35 PM, Matthew Pava wrote:

    You need to specify the field of the value in your ORM
    statement.  I don’t know what your field name is, but this
    assumes that it is “value”:

    aggregate(Sum(‘payment__value’))

    *From:*[email protected]
    <mailto:[email protected]>
    [mailto:[email protected]
    <mailto:[email protected]>] *On Behalf Of *Gerald Brown
    *Sent:* Monday, August 6, 2018 8:29 AM
    *To:* Django users
    *Subject:* Django ORM aggregate Sum function on foreign key

    Greetings:

    I am having a problem using the above function.

    In my table I have a field payment that is a foreign key to a
    payment table.

    When I try to use aggregate(sum('payment')) it gives me the sum
    of the foreign key, not the value from the payment table.

    Currently I have 9 records in my test DB each one has a foreign
    key of 3 so I get a sum of 27 not 2,250 that I should be getting.

    This table also has a foreign key to the customer table and it
    returns the customer not the foreign key number.

    The thought I had was to make that foreign key an integer field
    and then the user would have to enter a number instead of
    selecting it from a list, prone to operator errors,

    Any ideas on how I can get the correct totals using ORM.

    Thanks

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