Solved It.
It seems as of django 2.1, we need to add another parameter order_by
*Submission*.*objects*.values('user').annotate(Count('id')).order_by('user')
*documentation
<https://docs.djangoproject.com/en/dev/topics/db/aggregation/#interaction-with-default-ordering-or-order-by>*
*Thanks*
On Sunday, December 2, 2018 at 6:44:21 PM UTC+5:30, Coder Dude wrote:
>
> Here are my models:
> from django.contrib.auth.models import User as DefaultUser
> class Submission(models.Model):
> user = models.ForeignKey(to=DefaultUser,
> on_delete=models.CASCADE
> )
> total_score = models.DecimalField()
>
>
> The query that I am trying is :
>
> *Submission*.*objects*.values('user').annotate(Count('id'))
>
>
> I want to get the count of Submissions for each user
>
> But this returns me set of individual submission with count as 1
>
>
> *Output:*
>
> {'user': 1, 'id__count': 1}
> {'user': 1, 'id__count': 1}
> {'user': 1, 'id__count': 1}
> {'user': 1, 'id__count': 1}
> {'user': 2, 'id__count': 1}
> {'user': 2, 'id__count': 1}
> {'user': 3, 'id__count': 1}
>
>
> Whereas the output that I want is:
>
> {'user': 1, 'id__count': 4}
> {'user': 2, 'id__count': 2}
> {'user': 3, 'id__count': 1}
>
>
> What am I doing wrong?
>
> Please help
>
>
>
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