Try this one : paginator = Paginator(queryset_list,8) # Show 25 contacts per page page_request_var = "page" page = request.GET.get(page_request_var) try: queryset = paginator.page(page) except PageNotAnInteger: # If page is not an integer, deliver first page. queryset = paginator.page(1) except EmptyPage: # If page is out of range (e.g. 9999), deliver last page of results. queryset = paginator.page(paginator.num_pages)
Sent from Mail for Windows 10 From: leb dev Sent: Wednesday, September 25, 2019 2:32 PM To: Django users Subject: where is the error in pagination? i have a django project and it includes pagination i do not know where is the error in my code but once i tired to go to the next or previous page it crash and display the below error : > can only concatenate str(not ""NoneType) to str query=request.GET.get("search") paginator = Paginator(queryset_list, 5) page_request_var = "page" print("page_request_var===>",page_request_var) page = request.GET.get(page_request_var) print("page===>",page) queryset = paginator.get_page(page) print("queryset===>",queryset) When i print **page** it display None In the browser it suppose to display **page=2&search=sam** but instead it display **/?=2&20search%20=%20sam** -- You received this message because you are subscribed to the Google Groups "Django users" group. To unsubscribe from this group and stop receiving emails from it, send an email to django-users+unsubscr...@googlegroups.com. To view this discussion on the web visit https://groups.google.com/d/msgid/django-users/82e3fe0e-e872-4a49-b869-2b67001e3270%40googlegroups.com. -- You received this message because you are subscribed to the Google Groups "Django users" group. To unsubscribe from this group and stop receiving emails from it, send an email to django-users+unsubscr...@googlegroups.com. To view this discussion on the web visit https://groups.google.com/d/msgid/django-users/5d8b4c32.1c69fb81.58d02.1858%40mx.google.com.