As per the instructions provided in the Django Documentation 3.0, you are
restricted to get or generate only a single return value to each function
defined in views.py. *Instead*, as you stated, the* solution to your issue*
is that *creating hyperlinks in which the particular portion of the webpage
or website will be redirected to. By specifying explicitly that in your
case, "index.html" as the base to all other html files till you decide that
your Django Project Creation is Succeeded.*
I hope you understand.
I answered your question based on the title and issue posted by you. If you
are familiar with my description, its cool. Else, better to upload an image
containing the clear picture of communication conversations between the
urls which depends on your issue/requirement.
On Saturday, January 4, 2020 at 8:09:52 PM UTC+5:30, nrupesh08 wrote:
>
> hi,
> I design cms design on the company profile website.
> 5 pages on the website:
> index, about, services, projects, contact.
>
> the problem is,
> to display easily DB to frontend expect index page. because. all mixed
> retrieve DB. just main or sample of the display index page. like., about,
> service, project and contact.
>
> like,.: def index(request):
> content = {}
> return render(request, 'index.html', {})
>
> I want, like return values
> def index(request):
> content = {
> about, services(4 services displayed), projects(2 project
> displayed), contact
> }
> return render(request, 'index.html', {})
>
>
> but, *how to so many return values in one function?*
>
> please help me.
>
>
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