Hi,

from .. import abc is not working ?
or somewhat like that.

At last sys.path.append() is one of the solutions.

Cheers,
Naveen Arora


On Friday, 28 February 2020 16:38:15 UTC+5:30, Devender Kumar wrote:
>
> Hi,
> BTW it is flask app question.
>
> dir structure 
>  service 
>      config/__init__.py
>     config/config.py
>     src/app.py
>     src/__init__.py
>
> Running the flask app by writing command python src/app.py
>
> Question: I want to access config parameter in flask app from config 
> module of config package how can do that. 
>
> *solutions I tried* write *sys.path.append(''../")*  to my 
> src/__init__.py file but its not working please help me write this right 
> way.
>
> seems src/__init__.py is not being called.
>
> I don't want to change my dir structure and I don't want to write 
> *sys.path.append(''../")* in my app.py file, 
>
> Thanks in advance 
>
>

-- 
You received this message because you are subscribed to the Google Groups 
"Django users" group.
To unsubscribe from this group and stop receiving emails from it, send an email 
to [email protected].
To view this discussion on the web visit 
https://groups.google.com/d/msgid/django-users/83d12e3d-f5c3-4bd2-8e7f-a8b69b12afdc%40googlegroups.com.

Reply via email to