you mean request.method instead of request.post ?
On Thu, May 27, 2021 at 3:50 PM Bhanu prasad Ch <bp3545...@gmail.com> wrote:
> Hello Boris,
> I was thinking of passing number from the input to view function
> *call_me_when_ten()*
> *index.html*
> ...
> <input type= number name = "numbered"/>
> ...
>
> *views.py*
> def call_me_when_ten(request):
> if request.post == 'POST':
> number = request.POST['numberid']
> if number == 10:
> print('hello world')
> return render(request,'index.html')
>
> I got this code from StackOverflow, but this isn't worked. Please, help me
> in solving out this problem.
>
> On Wednesday, May 26, 2021 at 5:02:04 AM UTC+5:30 Boris Pérez wrote:
>
>> Hi!!! usually HttpResponseRedirects work with reverse
>> function...something like this
>> def myview(request):
>> return HttpResponseRedirect(reverse('arch-summary', args=[1945]))
>> where 'arch-summary' is the path name and args=[1945] the args it
>> expects...
>> You need to modify also your urls.py to add tyhe name argument to your
>> url...
>> Greetings
>>
>> 2021-05-25 0:57 GMT-04:00, Bhanu prasad Ch <bp35...@gmail.com>:
>> > Hello everyone,
>> > Please help me out in understanding how to pass the redirected view
>> > with some arguments like userid to connect the URLs in Django
>> > [image: Screenshot_2.png][image: Screenshot_3.png]
>> > When I am doing this way it is redirecting to the self page that is
>> login.
>> > But I need the
>> > HttpResponseRedirect to redirect to the progress.
>> >
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>>
>> >
>>
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