I have compiled SQLite 3.36.0 with Python3.9 but Django projects still show
the following error:
django.db.utils.NotSupportedError: deterministic=True requires SQLite 3.8.3
or higher
# python3.9
Python 3.9.6 (default, Jul 7 2021, 01:19:48)
[GCC 4.8.5 20150623 (Red Hat 4.8.5-44)] on linux
Type "help", "copyright", "credits" or "license" for more information.
>>> import sqlite3
>>> print(sqlite3.sqlite_version)
3.36.0
If I commented out the following section in settings.py, the error is gone
and the server can be started properly.
DATABASES = {
'default': {
'ENGINE': 'django.db.backends.sqlite3',
'NAME': BASE_DIR / 'db.sqlite3',
}
}
My question is, how did django determine sqlite3's version?
Before installing SQLite3.36.0, Python was using the old SQLite 3.7.17 and
the error message showed the lower version. Now that it is using the higher
version, the error message just said the subject line while the version is
definitely higher than 3.8.3 as you can see from the above output.
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