Hi to all.
I've add a generic list view with:
# Picture list:
(r'^museo/galleria/(?P<page>[0-9]+)/$',
'django.views.generic.list_detail.object_list',
dict(picture_list_info)),
and I want to add previous and next links.
It seems I must write an absolute url, in template, with:
{% if has_previous %}<a
href="http://localhost:8000/museo/galleria/{{previous}}";>Pagina
Precedente</a>{% endif %}
{% if has_next %}<a
href="http://localhost:8000/museo/galleria/{{next}}";>Pagina
Successiva</a>{% endif %}
Now I want to paginate the results of a search. The search use the
request.POST to filter results:
if request.POST['title'] != '':
query = query.filter(title__icontains=request.POST['title'])
and then:
return object_list(request, queryset=query)
how can I show the second page of my search results?
I've searched a lot on documentation, without results...
--
Alessandro Ronchi
Skype: aronchi - Wengo: aleronchi
http://www.alessandroronchi.net - Il mio sito personale
http://www.soasi.com - Sviluppo Software e Sistemi Open Source
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