Why can't it just be a "catch-all" url like:
(r'(?P<manufacturer>\w+)/', 'theview')
and then in your view:
def theview(request, manufacturer):
if manufacturer in my_manufacturers:
do_something()
else:
# error out with unknown manufacturer msg?
Greg wrote:
> I'm working on creating an e-commerce site in Django. I have a
> website that sells area rugs from 20 different manufacturers. I am
> wondering what the best way to configure my urls.py file. I've been
> thinking of a couple of different ways to accomplish this.
>
> 1) Contained all in one url line
> (r'^(mohawk|milliken|shaw|sphinx|etc...))/$', 'theview'),
>
> My 'theview' function would then find out what variable was passed to
> it. And then query that manufacturer table. So my url can get
> pretty long depending on how many manufacturers I have. Also, if I
> did it this way how would I setup my view? Would it be something like
> this
>
> def theview(request, manufacturer):
> rec = manufacturer.objects.all()
> return render_to_response('dispaly_manu.html', {'manu_records':
> rec})
>
> 2) Creating a separate url for each manufacturer
> (r'^/mohawk/$', 'django.views.generic.list_detail.object_list',
> mohawk_dict),
> (r'^/milliken/$', 'django.views.generic.list_detail.object_list',
> milliken_dict),
> (r'^/shaw/$', 'django.views.generic.list_detail.object_list',
> shaw_dict),
> (r'^/sphinx/$', 'django.views.generic.list_detail.object_list',
> sphinx_dict),
>
> This way seems like a waste. Would I need to create a unique
> dictionary for each manufacturer? Is there a way I can use the same
> dictionary for every manufacturer?
>
> Or does somebody have a better solution than what I came up with
> above?
>
> Thanks
>
>
> >
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