Christopher wrote: > Hi, > > I am pretty new to both Python and Django and have a quick and > hopefully easy question. Is it possible to create a Model with a link > back onto itself? > > Check the code below which does not seem to work. > > class Menu(models.Model): > display_text = models.CharField(maxlength=50) > url = models.URLField(verify_exists=False) > parent_menu_item = models.ForeignKey(Menu) > > I get the following error when I try to manage.py syncdb > > Error: Couldn't install apps, because there were errors in one or more > models: > totalimpact.menu: name 'Menu' is not defined >
Try something like this: models.ForeignKey("self") :-) There are some examples for this available with many-to-one relationships [1] [1] http://www.djangoproject.com/documentation/models/m2o_recursive/ - Horst --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~----------~----~----~----~------~----~------~--~---