This looks like a foreign key relationship (probably should be if it's not). Use ModelChoiceField instead of ChoiceField. I haven't used it manually in a form before, but try this:
instrument = ModelChoiceField(queryset=Instrument.objects.all(), cache_choices=False, required=False) Note that this will return the primary key of an instrument for the value, rather than the name. ---- Nathan Ostgard On Jul 10, 4:41 am, AnaReis <[EMAIL PROTECTED]> wrote: > Hi, > I have a form on my project which has a drop down list with several > options that are loaded from a table in a database. > The code is this: > > class ProductForm(forms.Form): > instrument_Name=ChoiceField(required=False, > choices=[(i.instrument_name,i.instrument_name) for i in > Instrument.objects.all()]) > > The problem is that whenever I add a new instrument to the instrument > table the instrument only appears on the drop down list if I restart > the server or after an hour (more or less) of when I added the > instrument. > I would like to know what can I do to make a new instrument appear on > the drop down list as soon as it is added, or what am I doing wrong. > Ana --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to [email protected] To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~----------~----~----~----~------~----~------~--~---
