list_display can use functions as their value... so, you can have:
class Employee(models.Model):
sub_dept = ForeignKey(SubDept)
def company(self):
return sub_dept.dept.company
def dept(self):
return sub_dept.dept
class Admin:
list_display = ('first_name, 'last_name', 'company', 'dept',
'sub_dept')
On Aug 1, 3:16 pm, Rohit <[EMAIL PROTECTED]> wrote:
> Actually my question is two fold, most likely due to brain farts on my
> end. I'm relatively a newbie to Django, so please bear with me.
>
> Here's my scenario. I have this for my relationships:
> Company->Dept->Sub-Dept->Employees->Roles
> "->" represents a one-to-many relationship.
>
> Problem #1:
>
> If I do something like this:
> Class Company(models.Model):
> name...
>
> Class Dept(models.Model):
> company = ForeignKey(Company)
> name...
>
> Class Sub-Dept(models.Model):
> dept = ForeignKey(Dept)
> name...
>
> Class Employee(models.Model):
> sub-dept = ForeignKey(Sub-Dept)
> first_name...
>
> Class Admin:
> list_display = ( 'first_name', 'last_name', 'sub-dept', )
>
> The problem is when I go into the admin screen and view employees,
> there is no way of displaying the company and dept. info next to the
> name of the employee. How can I accomplish that?
>
> Problem #2:
> This kinda arises from my efforts trying to fix Problem #1.
>
> I changed my code like so:
>
> .....
> .....
> Class Employee(models.Model):
> company = ForeignKey(Company)
> dept = ForeignKey(Dept)
> sub-dept = ForeignKey(Sub-Dept)
> first_name...
>
> Class Admin:
> list_display = ( 'first_name', 'last_name', 'company', 'dept',
> 'sub-dept', )
>
> Now the problem is when I add an employee, I have to add some kind of
> validation to the admin interface that checks whether the sub-dept,
> dept and company match. My main issue is where can I add this
> validation so that it is reflected in the admin interface?
>
> Thanks in advance for the pointers.
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