Sorry, think I've answered my own question: Further searching found a similar request in developers a couple of months back:
http://groups.google.com/group/django-developers/browse_thread/thread/ef2d981e49ba1b4d/a4c531b8b4880cd0 Which didn't get any love. So I guess I'll need to drop in to SQL for now. On Aug 14, 4:34 pm, NickJ <[EMAIL PROTECTED]> wrote: > Take 3 models: > > class Publisher(models.Model): > name = models.CharField() > > class Author(models.Model): > name = models.CharField() > > class Book(models.Model): > publisher = models.ForeignKey(Publisher) > authors = models.ManyToManyField(Author) > > i.e. a book must have one or more authors, and must have one > publisher. > > What i want is to get a distinct list of all authors for a specific > publisher. Is this possible without dropping back to raw SQL? > > I want to do something like: > > p = Publisher.objects.get(pk=1) > list = p.book_set.values('publisher__id', 'publisher__name').distinct() --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~----------~----~----~----~------~----~------~--~---
