Thank you Christoph. Yes I have tried a independent daemon, but that's a bit complicated for a small site. Is there a simipler way?
Simple is better. On Oct 10, 5:23 pm, Christoph Rauch <[EMAIL PROTECTED]> wrote: > est schrieb:> I am writing a GoogleTalk bot for my django site, but I don't > know > > were to initiate a xmpppy Client object in Django. Should I put it in > > my project's __init__.py ? I need the bot to be always online so where > > can I write a GLOBAL, long survival object in Django? How can I make > > I wouldn't put it into __init__.py > > Not knowing xmpppy, this may or may not be simple: > > I would build a seperate daemon and send commands to it from inside > your Django project. If you need the other way round, just import the > required models in your xmpp client and put some logic there. > > That way you can just fire off commands to the daemon without having > to worry about your connection. It's up to the daemon then. > > You can start the daemon completely separate of your webserver/Django > project. Just make sure that Django can connect to the daemon, e.g. > via unix domain sockets. Domain sockets are great, because you can > restrict access to it with basic filesystem rights. > > Christoph --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to [email protected] To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~----------~----~----~----~------~----~------~--~---
