There's a few things to put together -
urls.py needs something like (add a line before the normal admin
line):
(r'^admin/your_report/csv/$',
'yourproject.admin_views.report.csv_report'),
(r'^admin/', include('django.contrib.admin.urls')),
Then in your admin_views/report.py (or whatever you want to call it)
import csv
@staff_member_required
def csv_report(request):
# stuff here
# Create the HttpResponse object with the appropriate CSV header.
response = HttpResponse(mimetype='text/csv')
response['Content-Disposition'] = 'attachment;
filename=yournamehere.csv'
writer = csv.writer(response)
writer.writerow(['rowheader',
'rowheader','rowheader','rowheader',])
for obj in obj_list:
writer.writerow([stuff,stuff,stuff,stuff])
return response
There are more details within the DjangoBook but that should get you
looking in the right direction.
J
On Nov 9, 10:12 am, GodOfGeeks <[EMAIL PROTECTED]> wrote:
> Hello all,
>
> I would like to add a new button to the searching page called "Convert
> to CSV".
>
> When I press the button, I want to covert the currently displayed
> results to a CSV (Comma separated values)format.
>
> if you could give me some guide lines about how to do this I would be
> really grateful. What I did so far is to copy the
>
> search_form to a new templates folder in my project so now any changes
> i do in the search_form.html is reflected in
>
> in application.
>
> Thanks in advance
>
> Cheers
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