Hi Alex,
I want to do what you've shown me; print a list of games with the name
of the platform(s). I've been trying to find an answer to this in all
of the docs but the examples given never use real-world examples and
everything seems to be done on the Python shell, which is now how I am
using it. The views code is from examples I have found - I agree it is
strange and yours is much cleaner!
Thanks for your reply, I've got this semi-working now, only problem is
it has an error. With DEBUG=True on it gives this:
join requires 1 arguments, 0 provided
Does this mean no results (platforms) are being passed through?
On Jan 8, 9:35 pm, Alex Koshelev <[EMAIL PROTECTED]> wrote:
> What are you want to do? Do you read docs?
> The view's code is very strange. So many times appears word "list".
>
> May be you what get all games with platforms, so
>
> def games(request):
> games = Game.objects.all()
> return render_to_response('games/games.html',
> { 'games':games }, context_instance=RequestContext(request))
>
> {% for game in games %}
> Title: {{ game.title }} </br>
> Platform: {{game.platforms.all|join", "}}</br>
> {% endfor %}
>
> On 9 янв, 00:14, Darthmahon <[EMAIL PROTECTED]> wrote:
>
> > Hey,
>
> > Can't get my head around this. Basically I have a model that includes
> > a manytomany field like this:
>
> > ##########################
> > File: /games/models.py
> > ##########################
> > class Platform(models.Model):
> > title = models.CharField(maxlength=30)
>
> > def __unicode__(self):
> > return self.title
>
> > class Game(models.Model):
> > title = models.CharField(maxlength=30)
> > platforms = models.ManyToManyField(Platform)
>
> > def __unicode__(self):
> > return self.title
> > ##########################
>
> > I then request all of the games using this function:
>
> > ##########################
> > File: /games/views.py
> > ##########################
> > def games(request):
>
> > games_listing = []
> > games = Game.objects.all()
> > count = games.count()
> > for games_list in games:
> > games_dict = {}
> > games_dict['list_object'] = games_list
> > games_listing.append(games_dict)
> > return render_to_response('games/games.html', { 'games_listing':
> > games_listing, 'count': count },
> > context_instance=RequestContext(request))
> > ##########################
>
> > As you can see, it calls the template games/games.html which looks
> > like this:
>
> > ##########################
> > File: /games/views.py
> > ##########################
> > {% for list_dict in games_listing %}
> > Title: {{ list_dict.list_object.title }} </br>
> > Platform:{{ list_dict.list_object.platform.title }} </br>
> > {% endfor %}
> > ##########################
>
> > This is where I'm stuck. It prints out the name of the game, but
> > doesn't print out the name of the platform. I was assuming Django
> > would make it easy to print out the title of the Platform linked via
> > the ManyToMany field?
>
> > Any ideas?
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