Hey,
I have three models but I can only handle the relationship between two
at any one time.
Basically I have a page that needs to show a threads the current
user's friends are currently participating in. I.E. something like
this:
Thread: ABC
Participating: Friend 1
Thread: XYZ
Participating: Friend 1, Friend 2, Friend 3
Here are my models (both of which refer to the default Auth model):
----------------------------------
File: /people/models.py
----------------------------------
class UserProfile(models.Model):
user = models.ForeignKey(User, unique=True)
friends = models.ManyToManyField(User, blank=True,
related_name='friend_set')
----------------------------------
File: /thread/models.py
----------------------------------
class Thread(models.Model):
title = models.CharField(maxlength=200)
users = models.ManyToManyField(User, related_name='users')
----------------------------------
Now here is my view file:
----------------------------------
File: /people/views.py
----------------------------------
def index(request):
# get profile
profile = get_object_or_404(UserProfile,
user__id__exact=request.user.id)
# get friends for user
friends = profile.friends.all()
# get threads for friends
???????????
----------------------------------
As you can see, I don't know what to do now I need to get the threads
for each individual user. I don't need to group them in a special way,
I just want to print the threads my friends are currently
participating in an alphabetical list.
I did wonder if I should just edit the UserProfile model like this?
----------------------------------
File: /people/models.py
----------------------------------
class UserProfile(models.Model):
user = models.ForeignKey(User, unique=True)
friends = models.ManyToManyField(User, blank=True,
related_name='friend_set')
threads = models.ManyToManyField(Thread, blank=True,
related_name='thread_set')
----------------------------------
Any ideas on how to do this? I'm guessing it's probably fairly basic
but I can't think how I would get around this at the moment (it's been
a long week!) ;)
Cheers,
Chris
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