In your urlpatterns, you are passing a string for the value of
feed_dict ("feeds"). You need to pass the actual dictionary object
that you setup for yourself:
...{ 'feed_dict' : feeds }
Cheers
-Brian
On Mar 2, 10:39 am, Florian Lindner <[EMAIL PROTECTED]> wrote:
> Hello,
> I try to create an RSS feed for my blog.
>
> I have in my application urls.py:
>
> from feeds import *
> feeds = { 'latest' : LatestEntries, }
>
> urlpatterns = patterns("",
> [...],
> (r'^feeds/(?P<url>.*)/$', 'django.contrib.syndication.views.feed',
> {'feed_dict':'feeds'})
> )
>
> in feeds.py:
>
> from django.contrib.syndication.feeds import Feed
> from models import Entry
>
> class LatestEntries(Feed):
> title = "X-Ray Golf Mike"
> link = "/"
> description = "Some description"
>
> def items(self):
> return Entry.objects.order_by("-creationDate")[:10]
>
> my Entry model has a proper string representation (def __unicode__ is
> present).
>
> Now I try to access my latest feed, resulting in an error.
>
> http://localhost:8000/blog/feeds/latest/:
>
> File "/Users/florian/dev/django/django/core/handlers/base.py" in
> get_response 82. response = callback(request, *callback_args,
> **callback_kwargs) File "/Users/florian/dev/django/django/contrib/
> syndication/views.py" in feed 14. f = feed_dict[slug] Exception Type:
> TypeError at /blog/feeds/latest/ Exception Value: string indices must
> be integers
>
> Anyone got an idea what is wrong with my code? I use the latest SVN
> checkout.
>
> Thanks,
>
> Florian
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