it does not return any values.
I did post.0.title because the dictionary is established like this:
>>> test
{0: {'post': 'My First Post', 'title': 'My First Title'}, 1: {'post': 'My
Second Post', 'title': 'My Second Title'}}
and it goes on and on
If I could iterate over it, like post.0.title, then post.1.title and so
forth, it would be perfect
Thanks for your help
On Wed, Jun 18, 2008 at 2:42 PM, Joel Bernstein <[EMAIL PROTECTED]> wrote:
>
> I could be completely mistaken, but can't you replace 'post.0.title'
> and 'post.0.post' with 'x.title' and 'x.post', respectively?
>
> On Jun 17, 1:50 pm, "Juan Hernandez" <[EMAIL PROTECTED]> wrote:
> > Hey there
> >
> > I've been practicing for a while with the template system and I have some
> > questions:
> >
> > Lets say that I create this dictionary:
> >
> > test = dict()
> > test[0] = {'title': 'My First Title', 'post': 'My First Post'}
> > test[1] = {'title': 'My Second Title', 'post': 'My Second Post'}
> > etc... til 10 for example
> >
> > If i want to display that information, the best way would be to iterate
> over
> > each number and show 'title' and 'post'.
> >
> > My question is: How can I actually iterate over a dictionary like this
> > inside a template? If i do this (assuming that the shown dictionary has
> been
> > assigned to 'post' in render_to_response)
> >
> > {% for x in post%}
> > <h2><a href="#">{{ post.0.title }}</a></h2>^M
> > <br>
> > <br>
> > <p>{{ post.0.post }}</p>^M
> >
> > It will only show the first part of the dictionary and 'x' as a number
> > cannot be handled. I haven't found a way to have an increasing number to
> > iterate with... Something to replace the zero that increases until is
> > finished by hte condition
> >
> > What would be the best way to display the whole dictionary in a
> template??
> >
> > Thank you very much as usual
> > jhv
> >
>
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