http://www.djangoproject.com/documentation/url_dispatch/
look at the regular expressions used in the examples, and the section
"named groups"
On Jun 23, 9:22 am, sebastian stephenson <[EMAIL PROTECTED]> wrote:
> ok so I have in my data base a colium of rss feeds and I am parseing
> them via feedparser and I am having a touble getting one feed to have
> like "local/show/1" and another feed have "local/show/2" but how do
> you do this here is the urls.py in its current state:
>
> from django.conf.urls.defaults import *
>
> urlpatterns = patterns('',
> # Example:
> # (r'^ubermicro/', include('ubermicro.foo.urls')),
>
> # Uncomment this for admin:
> (r'^admin/', include('django.contrib.admin.urls')),
> #temp only fo dev proposes
> (r'^shows/','ubermicro.shows.views.show_page') # .* does not work
> )
>
> then views.py:
>
> from django.http import HttpResponse
> import feedparser
> from ubermicro.shows.models import show
> from django.template import Context, loader
>
> def show_page(request):
> """this is where we take what we need form the rss feeds in the
> data base"""
> query = show.objects.filter(show_feed__contains="http://";)
> for s in query:
> podcast = feedparser.parse(s.show_feed)
> if podcast.entries:
> elements = {'show_about':
> podcast.feed.summary,'show_latest_title': podcast.entries
> [0].title,'show_latest': podcast.entries[0].summary}
> e = elements
> t = loader.get_template('shows/show_page_base.html')
> return HttpResponse(t.render(Context(e)))
>
> just to say new to django and webdev python etc. so baby language
> please thank you very much in advance
>
> Thanks
> see ya
>
> sebey
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