On Jul 13, 6:10 am, Darthmahon <[EMAIL PROTECTED]> wrote: > Alex, > > I don't understand what you mean by that? message.users.all prints out > a list of users based on the many to many. I just want to check if the > current user is in message.users.all - are you saying I can't because > I am passing in a string, not an actual UserProfile instance? >
You are probably not passing in a UserProfile. Have you tried using a "raise Exception(value)" right after the signature of your filter to see what you are getting? @register.filter def IN(value,arg): raise Exception("Type of value: %s, Type of arg: %s" % (type(value), type(arg))) return value in arg --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~----------~----~----~----~------~----~------~--~---