try it without the {}
(r'^$','archive_index', dict(archive_dict, template_name='blog/
archive.html')),
On Sep 3, 9:07 am, Daniel Hepper <[EMAIL PROTECTED]> wrote:
> > could do dict(archive_dict, {'template_name': 'blog/archive.html'} )
>
> I don't think it's that easy. I get this:
>
> >>> dict(archive_dict, {'template_name': 'blog/archive.html'} )
>
> Traceback (most recent call last):
> File "<stdin>", line 1, in <module>
> TypeError: dict expected at most 1 arguments, got 2
>
> The only thing that comes to my mind is:
> dict(archive_info.items() + [('template_name','blog/archive.html')] )
>
> A bit messy though.
>
> > On Sep 3, 8:40 am, Daniel Hepper <[EMAIL PROTECTED]> wrote:
> > > Adding a comma will probably not help, because you then have 5 values in
> > > the tuple, but the expected format is:
>
> > > (regular expression, Python callback function [, optional dictionary [,
> > > optional name]])
>
> > > Either you put the argument 'template_name' into the archive_info dict
> > > or you make two separate dicts.
>
> > > Daniel
>
> > > Am Mittwoch, den 03.09.2008, 05:26 -0700 schrieb
> > > [EMAIL PROTECTED]:
>
> > > > i believe you need a comma after archive_info and before
> > > > {'template_name': 'blog/archive.html'}
>
> > > > On Sep 3, 7:40 am, djandrow <[EMAIL PROTECTED]> wrote:
> > > > > Can no one help me with this, its just these two lines:
>
> > > > > (r'^archive/$', date_based.archive_index,archive_info
> > > > > {'template_name': 'blog/archive.html'}),
> > > > > (r'^archive/(?P<year>d{4})/?$',date_based.archive_year, archive_info
> > > > > {'template_name': 'blog/archive.html'}),
>
> > > > > Please?
>
> > > > > Andrew
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