Hi Norman,

But if I have an empty file, models.py, that should thrown an error.

Thanks,

Kartik

On Sep 17, 1:45 pm, "Norman Harman" <[EMAIL PROTECTED]> wrote:
> Karthik Krishnan wrote:
> > The stack trace is given below
>
> > Traceback (most recent call last):
> >   File "manage.py", line 11, in <module>
> >     execute_manager(settings)
> >   File "c:\tools\Python25\Lib\site-packages\django\core\management
> > \__init__.py",
> >  line 340, in execute_manager
> >     utility.execute()
> >   File "c:\tools\Python25\Lib\site-packages\django\core\management
> > \__init__.py",
> >  line 295, in execute
> >     self.fetch_command(subcommand).run_from_argv(self.argv)
> >   File "c:\tools\Python25\Lib\site-packages\django\core\management
> > \base.py", lin
> > e 77, in run_from_argv
> >     self.execute(*args, **options.__dict__)
> >   File "c:\tools\Python25\Lib\site-packages\django\core\management
> > \base.py", lin
> > e 87, in execute
> >     translation.activate('en-us')
> >   File "c:\tools\Python25\Lib\site-packages\django\utils\translation
> > \__init__.py
> > ", line 73, in activate
> >     return real_activate(language)
> >   File "c:\tools\Python25\Lib\site-packages\django\utils\translation
> > \__init__.py
> > ", line 43, in delayed_loader
> >     return g['real_%s' % caller](*args, **kwargs)
> >   File "c:\tools\Python25\Lib\site-packages\django\utils\translation
> > \trans_real.
> > py", line 209, in activate
> >     _active[currentThread()] = translation(language)
> >   File "c:\tools\Python25\Lib\site-packages\django\utils\translation
> > \trans_real.
> > py", line 198, in translation
> >     default_translation = _fetch(settings.LANGUAGE_CODE)
> >   File "c:\tools\Python25\Lib\site-packages\django\utils\translation
> > \trans_real.
> > py", line 181, in _fetch
> >     app = getattr(__import__(appname[:p], {}, {}, [appname[p+1:]]),
> > appname[p+1:
> > ])
> >   File "c:\tools\Python25\Lib\site-packages\django\contrib\admin
> > \__init__.py", l
> > ine 1, in <module>
> >     from django.contrib.admin.options import ModelAdmin, HORIZONTAL,
> > VERTICAL
> >   File "c:\tools\Python25\Lib\site-packages\django\contrib\admin
> > \options.py", li
> > ne 5, in <module>
> >     from django.contrib.contenttypes.models import ContentType
> >   File "c:\tools\Python25\Lib\site-packages\django\contrib\contenttypes
> > \models.p
> > y", line 1, in <module>
> >     from django.db import models
> >   File "c:\tools\Python25\Lib\site-packages\django\db\models
> > \__init__.py", line
> > 5, in <module>
> >     from django.db.models.query import Q
> >   File "c:\tools\Python25\Lib\site-packages\django\db\models
> > \query.py", line 7,
> > in <module>
> >     from django.db.models.fields import DateField
> >   File "C:\tools\Python25\lib\site-packages\django\db\models\fields
> > \__init__.py"
> > , line 666
> >     class DecimalField(max_digits = 32, decimal_places =
> > 0)IntegerField(Field):
> >                                   ^
> > SyntaxError: invalid syntax
>
> > The stack trace does not define which line has an incorrect syntax. I
> > am having this error even there is nothing in the models.py file.
>
> It says it happened on line 666 of
> C:\tools\Python25\lib\site-packages\django\db\models\fields\__init__.py
> just at the equals sign "max_digits = 32".
>
> --
> Norman J. Harman Jr.
> Senior Web Specialist, Austin American-Statesman
> ___________________________________________________________________________
> Get off the sidelines and huddle up with the Statesman all season long
> for complete high school, college and pro coverage in print and online!
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