On Mon, Oct 13, 2008 at 4:22 AM, Alessandro Ronchi < [EMAIL PROTECTED]> wrote:
> 2008/10/11 Karen Tracey <[EMAIL PROTECTED]>: > > > You've got a typo in there somewhere, because there is no 'notizie' in > the > > query you posted, you've got 'schede' like above. So I'm not sure > exactly > > what you tried nor exactly what error you got. Cut and paste of code and > > error messages is best to avoid confusion. Also, posting complete models > > instead of just snippets (put them out on dpaste.com and point to them > if > > they are non-trivial and thus will display poorly in email) may be better > in > > this case. From what you posted so far I don't see why what (I'm > guessing) > > your query was isn't working. > > This is my models.py: > http://dpaste.com/84075/ > > This is my urls.py: > http://dpaste.com/84077/ > (che commented line is the one that gives the error) > # > ultima_edizione=Edizione.objects.distinct().filter(notizie__isnull=False).order_by('-id') > > > This is the error i Get: > > http://dpaste.com/84076/ > > Thanks in advance! > I can't recreate your error because any attempt to use the models.py you point to produces an error on the declaration of the Edizione ForeignKey field within model Notizia: edizione = models.ForeignKey(Edizione, related_name="notizie", default=ultima_edizione) NameError: name 'ultima_edizione' is not defined So I am not sure exactly how you are getting as far as you are with this models.py. (It's also missing any declaration of the model Download that is referenced in the urls.py you point at...) But I think you have a chicken-and-egg sort of problem since the line you are saying does not work is: ultima_edizione=Edizione.objects.distinct().filter(notizie__isnull=False).order_by('-id') So loading the Notizia model requires resolving ultima_edizione, but ultima_edizione requires the Notizia model to be fully initialized since it is the Edizione ForeignKey within Notizia which causes the 'notizie' attribue to be added to Edizione. (Also, even if this worked, ultima_edizone ends up being a QuerySet there, not an Edizione instance, so it wouldn't work as a default value.) Simply adding an import of the missing ultima_edizione to models.py produces an import error that Notizia cannot be imported due to the circular reference, in the backtrace you see: from urls import ultima_edizione ... from models import Notizia, Edizione ... from urls import ultima_edizione ... from models import Notizia, Edizione ImportError: cannot import name Notizia which is what I would expect given what you have. So I'm not sure how you are getting around the circular import but it seems to result in ultima_edizione being processed using an incompletely loaded model set, since Edizione does not have the attribute that will be created when the Notzia model is loaded. I think you need to take a step back and rethink that default= on the edizione ForeignKey. What are you really trying to accomplish? Karen --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~----------~----~----~----~------~----~------~--~---
