>> http://docs.python.org/lib/re-syntax.html
>>
>> There are several good books and websites that will teach you the
>> basics of regexps, and a quick search will bring back a number of
>> results.
>
> Thank alot thats the best response I have had.
Glad to help...though in a way, it's as much a Python or regexp
question as a Django question.
> What is: one or more times "+" mean?
It looks at the "atom" (atom is the word used to describe "a
thing"...a single character, a set of characters, or other group
of expressions designated as a single unit) before it. A few
examples, as well as a counterpoint with "*" ("zero or more
times") and the "{X}"/"{X,Y}" ("exactly X repetitions" and
"between X and Y repetitions") notation.
An empty string would match "^a*$" because it contains "zero or
more "a"s.
The string "foo" would match "^fooa*" because it's "foo" followed
by zero or more "a"s. (note that "a" is the atom because it's
what immediately precedes the "*")
However neither the empty string nor "foo" would match if the "*"
was now a "+" because you would need at least *one* (or more) "a"s.
The string "aaaaaaaa" would match both "a*" and "a+" because
there are "zero or more" of the letter a.
As a more complex example, you can use something other than a
single letter as an atom:
The pattern "^[aeiou]*$" will only match strings that are all
vowels or are empty, while "^[^aeiou]*$" will only match strings
that are all consonants or empty. Changing the "*" to a "+"
requires that there be at least one vowel/consonant for a match,
and thus would fail to match the empty string.
Lastly, just as an example of the "{...}" repetition items, the
pattern "^\d{4}$" would match exactly 4 digits, while
"^\w{5,15}$" would match 5-15 "word" characters (as previously
described as alphanumerics plus underscore).
> How would I pass the whole date like 12/25/2008, I is freaking out
> about the '/'?
You have to be careful how you pass these strings, but you could
match such a pattern with
"\d{1,2}/\d{1,2}/\d{4}"
which can be wrapped in a named capture:
"(?P<start_date>\d{1,2}/\d{1,2}/\d{4})"
for a view that takes a parameter of "start_date"
Just remember that when it gets passed to your view:
1) it's a string, not a date
2) it's a pretty loose date pattern, so it does match
"99/42/9876" so you'd have to try converting it to a date and
then respond accordingly (if it's valid, then yay. if it's
bogus, let the user know to fix it)
I'll reassert that you would do well to read a couple
web-tutorials or pick up a book on regular expressions. They're
a very powerful tool in the programmer's tool-belt.
Hope this helps,
-tim
--~--~---------~--~----~------------~-------~--~----~
You received this message because you are subscribed to the Google Groups
"Django users" group.
To post to this group, send email to [email protected]
To unsubscribe from this group, send email to [EMAIL PROTECTED]
For more options, visit this group at
http://groups.google.com/group/django-users?hl=en
-~----------~----~----~----~------~----~------~--~---
