Hi,
I have a small form on a page that is mostly optional fields with the
exception of some drop down boxes. I want to take the data submitted
through this form and use them to form a URL.
My problem is with the URL writing. I first wrote some unit tests to
find the regular expressions that worked but Django doesn't seem to
like the '?' in URL configurations.
How can I write a workflow that converts optional, POSTed data to a
RESTful URL for processing?
Here's an example:
class IceCreamForm(forms.form):
description = forms.CharField(required=False)
flavour = forms.ChoiceField(choices=FLAVOUR_CHOICES, initial=0)
FLAVOUR_CHOICES = (
...
)
This is my form class. It contains one optional field, and one
required field. When rendered on a page, the form POSTs it's data to
the the 'process' view:
def process(request):
# Standard form stuff (is_valid) ...
params = {}
if form.cleaned_data['description']:
params.update(description=form.cleaned_data['description'])
if form.cleaned_data['flavour']:
params.update(flavour=form.cleaned_data['flavour'])
return HttpResponseRedirect('proj.app.views.filter', kwags=params)
def filter(request, description=None, flavour=0):
... do stuff ...
Here, I collect the parameters from the form and try to turn them into
a pretty URL that redirects to the filter view to do something with
the data. It's the URL writing I'm having problems with. I want to
write things like:
urlpatterns += patterns('proj.app.views',
(r'^(?P<flavour>\w+)/((?P<description>\w+)/)?$', 'filter'),
)
The question mark is wrapped around an extra '/' to complete the URL,
but it doesn't work. Nor does
urlpatterns += patterns('proj.app.views',
(r'^(?P<flavour>\w+)/$', 'filter'),
(r'^(?P<flavour>\w+)/(?P<description>\w+/$', 'filter'),
)
I'm surprised with the result of the last one, and so I'm sure I'm
missing something. Does anyone have any ideas or simplifications for
me?
Thanks,
Red Monkey
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