You have to convert value from string to integer:
int(arg)
On Wed, Nov 19, 2008 at 13:18, K*K <[EMAIL PROTECTED]> wrote:
>
> I modified some code so I made mistake again. -_-#
>
> The right result looks like this:
>
> $ ./manage.py shell
> Python 2.5.1 (r251:54863, Apr 15 2008, 22:57:26)
> [GCC 4.0.1 (Apple Inc. build 5465)] on darwin
> Type "help", "copyright", "credits" or "license" for more information.
> (InteractiveConsole)
> >>> from addressbook.core.templatetags.extra_filters import cut_by_string
> >>> cut_by_string("Hello World", 3)
> u'...'
> >>> cut_by_string("Hello World", 5)
> u'He...'
> >>> cut_by_string("Hello World", 10)
> u'Hello W...'
> >>> cut_by_string("Hello World", 15)
> u'Hello World'
> >>>
>
>
> On Nov 19, 6:09 pm, Daniel Roseman <[EMAIL PROTECTED]>
> wrote:
> > On Nov 19, 9:52 am, "K*K" <[EMAIL PROTECTED]> wrote:
> >
> >
> >
> > > Hi, All.
> >
> > > I create a custom filter for cut too long string for my app.
> >
> > > Like this:
> >
> > > from django import template
> > > from django.template.defaultfilters import stringfilter
> >
> > > register = template.Library()
> >
> > > @register.filter(name='cut_by_string')
> > > @stringfilter
> > > def cut_by_string(value, arg):
> > > if len(value) < arg:
> > > return value
> > > else:
> > > return value[:arg-3] + "..."
> >
> > > And in the template I load the filter .py normally, and set below
> > > codes:
> >
> > > <div><a href="#">{{ testplan.name|cut_by_string:"a"
> }}</a></div>
> >
> > > But it doesn't work, do I make any mistake in this code ?
> >
> > I'm not quite sure what the filter is supposed to do, but you're
> > passing a string and then checking if its length is 'less than'
> > another string. This doesn't make sense. This line would seem to be
> > the problem:
> > if len(value) < arg:
> > According to the values you've passed, this evaluates to:
> > if len('string') < 'a':
> > which will always be true.
> >
> > I wonder if you meant
> > if len(value) < len(arg)
> > ??
> >
> > --
> > DR.
> >
>
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