Dear Ronny/all,
Thank you for your reply. I have modified my code and the error still
occur.
my new code as following below:
def my_view(request):
username = request.POST['username']
password = request.POST['password']
user = authenticate(username=username, password=password)#create
Authentication object
render_to_response ('login.html', {'username': username,
'password' : password})
if user is not None:
if user.is_active:
login(request,user)
return render_to_response('success.html',
{'username':username})
else:
return HttpResponse('disabled account')
else:
return HttpResponse('invalid login')
and my login.html as per below:
<form action="/login/" method="POST">
Enter Username: <input type=text name="username">
Enter Password: <input type=password name="password">
<input type="submit" Value="Login"/>
</form>
my success.html as per below :
<html>
<h1> welcome{{username}}</h1>
</html>
somebody kindly help and thank you in advance
On Dec 6, 12:05 am, "Ronny Haryanto" <[email protected]> wrote:
> On Sat, Dec 6, 2008 at 2:42 PM, vierda <[email protected]> wrote:
> > today I try to make login page with follow example code in
> > djangoproject (user authentication chapter), code as following below :
>
> > def my_view(request):
> > username = request.POST['username']
> > password = request.POST['password']
> > user = authenticate(username=username, password=password)#create
> > Authentication object
>
> > if user is not None:
> > if user.is_active:
> > login(request,user)
> > return HttpResponse('login success')
> > else:
> > return HttpResponse('disable account')
> > else:
> > return HttpResponse('invalid login')
>
> > the above code always shows MultiValueDictKeyError with exception
> > value "Key 'username' not found in <QueryDict: {}>".
>
> That exception will always be raised if the view is called via GET
> method instead of POST.
>
> If you're sending it via POST, then the information you provided was
> not sufficient. We need to see template code that renders the form (or
> the html form if you're not using templates) and probably the form as
> well.
>
> Ronny
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