So you need to trigger an action the first time you save an object in
to the database.
----------------------
Class A:
#self.id is None whenever a particular instance has not been saved
into a database
#override save method in the object as follows
def save(self) :
firstime = false
if ~self.id :
firsttime = true
super.save()
#this code only fires only when it is being saved for the first
time.
if firstime :
#Trigger an action whichevery you want.................
---------------------------------
Hope the above code helps you in resolving the problem.
On Mar 6, 11:02 am, "[email protected]" <[email protected]> wrote:
> Sorry for the unwieldy title, but nothing else strikes me at the
> moment.
>
> I have a blog app -- a version of basic.blog, actually. There's a
> field in the model called "status" with two options: "draft" and
> "public."
>
> What I want to do is trigger an action the first time (and /only/ the
> first time) a particular instance is saved as "public."
>
> So:
>
> Write a post in the admin, save as draft --> No action
> Edit the post some, save as draft again --> No action
> Edit more, publish --> Action triggered!
> Edit again --> No action.
>
> How would I go about this? My thought is to override save(), but I
> can't figure out how to inspect the instance at that point to
> determine if the status attribute has changed since it was created. I
> assume that this information must be in there somewhere, since it
> seems like you'd need it to generate the SQL statement.
--~--~---------~--~----~------------~-------~--~----~
You received this message because you are subscribed to the Google Groups
"Django users" group.
To post to this group, send email to [email protected]
To unsubscribe from this group, send email to
[email protected]
For more options, visit this group at
http://groups.google.com/group/django-users?hl=en
-~----------~----~----~----~------~----~------~--~---
