On Mar 11, 12:57 pm, Ty <brownellty...@gmail.com> wrote:
> I need to validate an uploaded XML file in my Form clean method, but
> I'm unable to open the file for validation. It seams, in the clean
> method, the file hasn't yet been moved from memory (or the temporary
> directory) to the destination directory.
>
> For example the following code would fail because the file hasn't been
> moved to that destination yet. It's still in memory (or the temporary
> directory):
>
> # This is in my Form clean method:
> xml_file = cleaned_data.get('xml_file')
> xml_file_absolute = '%(1)s%(2)s' % {'1': settings.MEDIA_ROOT, '2':
> xml_file}
> xml_size = str(os.path.getsize(xml_file_absolute))
>
> When I look at the "cleaned_data" variable it shows this:
> {'xml_file': <InMemoryUploadedFile: texting.nzb (application/octet-
> stream)>}
>
> cleaned_data.get('xml_file') only returns "texting.nzb" as a string.
>
> Is there another way to access the the file in memory (or the
> temporary directory)?
What you get in cleaned_data can double as an open file handle from
which you can directly start reading:
xml_file = cleaned_data.get('xml_file')
value = xml_file.read()
# Do whatever validation you need on value
xml_file.seek(0) # Reset the file to the beginning as you found it.
Obviously, for larger files, you should read and process the data in
smaller
chunks instead of the above xml_file.read().
There's more info here:
http://docs.djangoproject.com/en/dev/topics/http/file-uploads/#handling-uploaded-files
-Rajesh D
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