You wouldn't match this using a url pattern. The rest of the query
string will be in the request.GET list. So you can do the following:
ui=request.GET['ui']
shva=request.GET['shva']
name=request.GET['name']
you'll probably want to check that it exists first by doing:
if 'ui' in request.GET:
ui=request.GET['ui']
or you can default it by doing:
ui=request.GET.get('ui','defaultvalue')
W
-----Original Message-----
From: [email protected]
[mailto:[email protected]] On Behalf Of MohanParthasarathy
Sent: Friday, May 15, 2009 5:56 PM
To: Django users
Subject: Parsing the arguments in HTTP GET
Hi,
I am very new to django. I am following along the tutorial. But I want
to be able to parse the URL which has the following form:
http://example.com/data/?ui=2&shva=1#label&name=xxxx/fetch
>From what I can tell, i can't match the whole thing using the url
pattern. I can parse up till "http://example.com/data" and the rest in
the code. Where can i find examples/tutorials for the above format ?
thanks
mohan
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