Strange :( This code produces nothing in template.... how can I debug it? Please help
2009/5/20 Oleg Oltar <[email protected]> > Just want to tell you big big thank you! > > > On Wed, May 20, 2009 at 10:52 PM, Alex Gaynor <[email protected]>wrote: > >> >> >> 2009/5/20 Oleg Oltar <[email protected]> >> >>> Is there any doc I can read about it? >>> >>> On Wed, May 20, 2009 at 9:50 PM, Alex Gaynor <[email protected]>wrote: >>> >>>> >>>> >>>> 2009/5/20 Oleg Oltar <[email protected]> >>>> >>>>> Ok, I got it now >>>>> What about the inheritance? Question 2? >>>>> >>>>> On Wed, May 20, 2009 at 9:30 PM, Alex Gaynor <[email protected]>wrote: >>>>> >>>>>> >>>>>> >>>>>> 2009/5/20 Oleg Oltar <[email protected]> >>>>>> >>>>>> Hi! >>>>>>> I have a model with a Sections and Categories related this way: >>>>>>> >>>>>>> class Category(models.Model): >>>>>>> categoty = models.CharField(max_length=200) >>>>>>> name = models.CharField(max_length = 200, help_text=u"Имя >>>>>>> категории") >>>>>>> >>>>>>> def __unicode__(self): >>>>>>> return u"Категория %s" %self.name >>>>>>> >>>>>>> class Section(models.Model): >>>>>>> section = models.CharField(max_length=200, unique=True) >>>>>>> name = models.CharField(max_length=200, blank = True) >>>>>>> category = models.ForeignKey(Category, blank=True) >>>>>>> >>>>>>> def __unicode__(self): >>>>>>> return u"%s" %(self.section) >>>>>>> >>>>>>> >>>>>>> I passed a categories to the template. Is there a way I can display >>>>>>> all sections related to each category in template? >>>>>>> >>>>>>> Not sure how to do it? >>>>>>> >>>>>>> {% for category in categories %} >>>>>>> <ul> >>>>>>> <li id="csstip" class="x"><a href="{{ category.category }}">{{ >>>>>>> category.name}}</a> >>>>>>> {% for section in %} >>>>>>> But how to get all sections from one category? >>>>>>> </li> >>>>>>> >>>>>>> And the second question >>>>>>> >>>>>>> If I am passing a variable to the base template (I want to use the >>>>>>> code to generate menu from categories), how to handle it in separate >>>>>>> (extended templates)? E.g. do I have to query categories in each my >>>>>>> view and >>>>>>> pass it as value to all templates I use? >>>>>>> >>>>>>> >>>>>>> Thanks in advance >>>>>>> Oleg >>>>>>> >>>>>>> >>>>>>> >>>>>>> >>>>>> {% for section in category_object.section_set.all %} >>>>>> >>>>>> {% endfor %} >>>>>> >>>>>> As documented here: >>>>>> http://docs.djangoproject.com/en/dev/topics/db/queries/#many-to-many-relationships >>>>>> >>>>>> Alex >>>>>> >>>>>> -- >>>>>> "I disapprove of what you say, but I will defend to the death your >>>>>> right to say it." --Voltaire >>>>>> "The people's good is the highest law."--Cicero >>>>>> >>>>>> >>>>>> >>>>> >>>>> >>>>> >>>> Right, there are 2 solutions to that (that I can think of). 1 is to >>>> write a template context processor. The other is to write a custom >>>> inclusion template tag. I personally favor the 2nd one because it gives >>>> you >>>> a little bit more control. >>>> >>>> >>>> Alex >>>> >>>> -- >>>> "I disapprove of what you say, but I will defend to the death your right >>>> to say it." --Voltaire >>>> "The people's good is the highest law."--Cicero >>>> >>>> >>>> >>> >>> >>> >> Right, sorry: >> >> context processors: >> http://www.b-list.org/weblog/2006/jun/14/django-tips-template-context-processors/ >> >> inclusion tag: >> http://docs.djangoproject.com/en/dev/howto/custom-template-tags/#inclusion-tags >> >> >> Alex >> >> -- >> "I disapprove of what you say, but I will defend to the death your right >> to say it." --Voltaire >> "The people's good is the highest law."--Cicero >> >> >> >> > --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to [email protected] To unsubscribe from this group, send email to [email protected] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~----------~----~----~----~------~----~------~--~---
