Thanks Amit. Here is the problem that I meet.
alerts = Alert.objects.filter((Q(dataset=dataset1)
for eachalert in alerts:
e_metric1 = eachalert.criteria1_metric1
Django complains that there is no such item "criteria1_metric1" in
Alert class. This is correct as Alert class does not have such an
item. The "criteria1_metric1" is a variable here that has a value. And
this value is an item in the Alert class.
How to let Django know that the "criteria1_metric1" is a variable
instead of a class item (table column)?
Thanks again.
On Jul 13, 2:14 pm, Amit Sethi <amit.pureene...@gmail.com> wrote:
> I am not sure what you are trying to do. And the code seems almost unreadable
> .
> You could try posting the code to :http://pastebin.com/
>
> Also what might be helpful:
> What is the problem statement what is this code trying to solve ?
>
> What value you want and where ?
>
> And what error does django give ...
>
> --
> A-M-I-T S|S
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