在 2009-7-20，0:33，Alex Gaynor <[email protected]> 写到：
> > On Sun, Jul 19, 2009 at 10:48 AM, aXqd<[email protected]> wrote: >> >> Hi, all: >> >> Recently, I linked two models ( FOO & BAR ) with a foreign key. >> Then I retrieved the whole records back with the following codes: >> >> 1 for item in FOO.objects.all(): >> 2 print item.bar.id >> >> In my opinion, the whole thing should be lazy enough. >> So if Line 1 got all the BAR id back, *WHY* did Line 2 still >> trigger a >> SQL query to retrieve the whole BAR object while all I want here was >> just that ID, which, I think, was already known by django at this >> time? >> Am I missing something here? >> >> Thanks. >> >> -- >> Regards. >> -Tian >> >>> >> > > Try doing item.bar_id. Doing item.bar causes Django to load up the > bar object, but if all you want is the id you can use "bar_id". > > Alex > > -- > "I disapprove of what you say, but I will defend to the death your > right to say it." -- Voltaire > "The people's good is the highest law." -- Cicero > "Code can always be simpler than you think, but never as simple as you > want" -- Me > > > It works. Thanks very much :) --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to [email protected] To unsubscribe from this group, send email to [email protected] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~----------~----~----~----~------~----~------~--~---
