hey susanne, sorry i could not help as i gave up that aplication. perhaps some one surely can help u here
On Jul 31, 1:36 am, susanne <[email protected]> wrote: > Hello Mr.pallavi, Mr.George and other members, > I have similar application like palavi. I followed this hints but not > success. > Please let me know how did you proceed. > > my python application has functions to perform different > calculations. > > 1) The program reads input file called IN.txt. > the IN.txt file contains names of three other files( x.dat, y.txt, > z.dat) that are > in the same directory. > > 2) then the application reads the data in the files x.dat, y.txt, > z.dat and performs some calculations. > > 3) outputs the results in a file called out.txt > > The application is running perfectly from command mode. I need to make > it a web application so that it can be run in a browser from anywhere. > I tried with cherrypy and django tutorials, but could not succeed, as > i am completely new to this field. can some one help with steps to > proceed. > > Thanks in advance! > Susanne > > > > > > > My main python program is science.py > > it have several modules.in it (each definition reads some parameters > > and results some data, that will be read > > by next module). but at the end, only few of the results are printed > > to a data file. > > science.py > > --------------- > > def function1(parameter1,parmeter2) : > > { > > ----- > > ----- > > } > > return data1 > > def function2(data1,parmeter3) : > > { > > ----- > > ----- > > } > > return data2 > > #output is printed to a file as data.dat that contains data1, data2 > > view.py > > ------------ > > from django.http import HttpResponse > > from science import function1 > > from science import function2 > > def science_service(request): > > return HttpResponse( > > # function1 reads parameter1, and parameter2 > > function1 (parameter1, parameter2), , mimetype="text/plain" > > ) > > def science_service(request): > > return HttpResponse( > > function2 (data1, parameter3), , mimetype="text/plain" > > ) > > is this the correct way to write my view based on George's > > suggestion: > > i keep my science.py in the current working directory. > > pls shed some light....your suggestions are very valuable for novice > > like me. > > You're on the right track. > > 1. You can't name both views the same, if they're in the same module. > Otherwise the second definition will override the first one. > 2. There's a slight mistake in your response: > {{{ > def science_service(request): > return HttpResponse( > function1(p1, p2), mimetype="text/plain" > ) > > }}} > > Of course you'll have to instantiate p1 and p2 somewhere in the > module, > if you're not passing those in through the request somehow. > > -- > George- Hide quoted text - > > - Show quoted text - --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to [email protected] To unsubscribe from this group, send email to [email protected] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~----------~----~----~----~------~----~------~--~---
