I don't use a modelform because one folder of my form is a ChoiceField. Regards
Luca On 20 Ago, 12:52, Daniel Roseman <[email protected]> wrote: > On Aug 20, 10:37 am, luca72 <[email protected]> wrote: > > > > > Hello i have made this it works, but i'm sure that there is a short > > way to obtain the same result can you tell me how? > > > def richiedi(request): > > if request.method == 'POST': > > form = RichiestaForm(request.POST) > > if form.is_valid(): > > tipo = form.cleaned_data['tipo'] > > nome_rich = form.cleaned_data['nome_rich'] > > > luca = Richiesta(tipo=tipo,nome_rich=nome_rich) > > luca.save() > > grazie = 'test' > > return render_to_response('grazie.html', > > {'grazie':grazie}) > > else : > > form = RichiestaForm() > > return render_to_response('richiedi.html',{'form': form}) > > > Thanks > > > Luca > > Yes: use a modelform. You haven't explained why you don't want to use > one. Your other thread just asked how to do it without a modelform, > and this is the answer to that. But the answer to do it with less code > is to use one. > -- > DR. --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to [email protected] To unsubscribe from this group, send email to [email protected] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~----------~----~----~----~------~----~------~--~---
