Hello ...
I have a tree like structure created out of models using ForeignKey
linkages. As an example:
Model Person:
name = CharField
Model Book:
name = CharField
author = FK(Person)
Model Movie:
name = CharField
director = FK(Person)
Model Album:
name = CharField
director = FK(Person)
Model Chapter:
name = CharField
book = FK(Book)
Model Scene:
name = CharField
movie = FK(Movie)
Model Song:
name = CharField
album = FK(Album)
The caveat here is the real structure is both deeper and broader, and a
node might have multiple non-FK fields (ie not just 'name').
What I'd like to do is have a search function such that there is a string
supplied which will return any Person that either matches a Person object
itself, or a field in any of the child nodes. IOW, if "beat it" is the
string, and the name of a song associated with an album associated w/ the
person matches, the person will be returned.
What I've done so far is the following:
For any leaf node, have a Manager object w/ a search method which does
something like:
return Song.objects.filter(name__icontains=search_string)
Then for the root node (Person) and any interior nodes, there is also a
Manager object w/ a search() method which looks something like:
class AlbumManager(models.Model):
def search(self, search_string):
from_songs =
Album.objects.filter(song__in=Song.objects.search(search_string))
return Album.objects.filter(name__icontains=search_string)|from_songs
As you might imagine, once you get to the root node, this unleashes a
massive number of queries and is really inefficient. I'd be pretty
surprised if there wasn't a better way to do this ... one idea is to just
have one search() method at the top of the tree that manually searches
through everything, but a) that seems very messy (albeit probably more
efficient) and b) it would be nice to be able to search individual nodes
arbitrarily.
So with all of this said, what would be a more efficient method of getting
where I want to be instead of my bonehead method here?
Thanks
-J
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